
Cheer, Rodolfo M. Kurchan
PUZZLE FUN Editor
| #592 | I have the 5 tetrominoes, and I quintuplicate one, then I cuadruplicate other, I triplicate the 3rd one, duplicate the 4th one and I have the last one single. The area of the five pieces is 220 and I want to put them in the rectangle of smallest area. My best solution is: 13 x 18 = 234 - 220 = 14 ![]() |
| #593 | as #592 but for pentominoes, from 1 single to one 12 times bigger. The area is: 3250 |
| #594 | I want to fill the biggest area rectangle with the tetrominoes inflated from 1 to 5, allowing overlaping squares, my best solution is: 1 to 5: 14 x 14 = 196 - 220 = 24![]() |
Rodolfo Marcelo Kurchan / Lavalle 3340 21"3" / (1190) Buenos Aires - Argentina
eMail: rodolfo@kurchan.com.ar
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